The inner diameter of a cylindrical wooden pipe is 24 cm and its outer diameter is 28 cm. The length of the pipe is 35 cm. Find the mass of the pipe, if 1 cm^{3} of wood has a mass of 0.6 g.

`["Assume "pi=22/7]`

Advertisement Remove all ads

#### Solution

Inner radius (*r*_{1}) of cylindrical pipe = (24/2)cm = 12 cm

Outer radius (*r*_{2}) of cylindrical pipe = (28/2)cm = 14 cm

Height (*h*) of pipe = Length of pipe = 35 cm

`"Volume of pipe "= pi(r_2^2-r_1^2)h`

`=[22/7xx(14^2-12^2)xx35]cm^3`

= 110 x 52 cm^{3}

= 5720 cm^{3}

Mass of 1 cm^{3} wood = 0.6 g

Mass of 5720 cm^{3} wood = (5720 × 0.6) g

= 3432 g

= 3.432 kg

Concept: Volume of a Cylinder

Is there an error in this question or solution?

#### APPEARS IN

Advertisement Remove all ads